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About LinkBacksThe length of each dimension of a cone is increased by 20%.
a. What is the percent increase in the surface area of the resulting figure?
b. What is the percent increase in the volume of the resulting figure?
Explain your answer.
The length of each dimension of a cone is increased by 20%.
a. What is the percent increase in the surface area of the resulting figure?
b. What is the percent increase in the volume of the resulting figure?
Explain your answer.
the fact that the solid is a cone is immaterial ...Originally Posted by monkeymath
if you increase each linear dimension by 20%, then the area will be increased by $\displaystyle \frac{(1.2)^2}{(1)^2} = 44$%
same idea for the volume, except that the linear dimensions are efectively cubed ... $\displaystyle \frac{(1.2)^3}{(1)^2} = 72.8$%
check it out using some actual values for any solid ... try something simple like a cube.
Hmm... They were supposed to have covered this topic before you were assigned homework on it...
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