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Math Help - The function of g

  1. #1
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    The function of g

    Please can anyone give some direction.
    The function:
    g(x)=1/4(x-2)^2-4 (4<x<8)
    has the same rule as the function f but has a smaller domain. I have to state the domain and image set of g^-1and find its rule.
    Anyone know where I start?
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  2. #2
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    Quote Originally Posted by stewpot View Post
    The function:

    g(x)=1/4(x-2)^2-4 (4<x<8)

    has the same rule as the function f but has a smaller domain.
    What is "f"? How is it necessary for this exercise?

    Your formatting is ambiguous. Do you mean the following?

    . . . . . g(x)\, =\, \frac{1}{4(x\, -\, 2)^2}\, -\, 4\, \mbox{ for }\, 4\, \leq \, x\, \leq \, 8

    Quote Originally Posted by stewpot View Post
    I have to state the domain and image set of g^-1and find its rule. Anyone know where I start?
    The domain of g is given to you in the exercise. The range (the "image set") of g-inverse will be the domain of g, by definition of "inverse". The domain of g-inverse will be the range of g, which you can "see" from the graph of g.

    To learn how to find the inverse of a function, try here. If you get stuck, kindly please reply with a clarification of the function g, along with a clear listing of your steps and reasoning so far.

    Thank you!
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