Please can anyone give some direction.

The function:

g(x)=1/4(x-2)^2-4 (4<x<8)

has the same rule as the function f but has a smaller domain. I have to state the domain and image set of g^-1and find its rule.

Anyone know where I start?

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- Mar 20th 2009, 04:06 AMstewpotThe function of g
Please can anyone give some direction.

The function:

g(x)=1/4(x-2)^2-4 (4__<__x__<__8)

has the same rule as the function f but has a smaller domain. I have to state the domain and image set of g^-1and find its rule.

Anyone know where I start? - Mar 20th 2009, 04:40 AMstapel
What is "f"? How is it necessary for this exercise?

Your**formatting**is ambiguous. Do you mean the following?

. . . . .$\displaystyle g(x)\, =\, \frac{1}{4(x\, -\, 2)^2}\, -\, 4\, \mbox{ for }\, 4\, \leq \, x\, \leq \, 8$

The domain of g is given to you in the exercise. The range (the "image set") of g-inverse will be the domain of g, by definition of "inverse". The domain of g-inverse will be the range of g, which you can "see" from the graph of g. (Wink)

To learn how to find the inverse of a function, try**here**. If you get stuck, kindly please reply with a clarification of the function g, along with a clear listing of your steps and reasoning so far.

Thank you! :D