# Thread: Need Help with this distance problem

1. ## Need Help with this distance problem

• Two cars start off at the same point on a straight road facing opposite directions. Each car drives for six miles, takes a left turn, and drives for eight miles. How far apart are the two cars?
a• 2 miles
b• 11 miles
c• 14 miles
d• 20 miles
e• 26 miles

Please tell me exactly how you came up with your answer

Thank you!!

2. Originally Posted by adamnn2006
• Two cars start off at the same point on a straight road facing opposite directions. Each car drives for six miles, takes a left turn, and drives for eight miles. How far apart are the two cars?
a• 2 miles
b• 11 miles
c• 14 miles
d• 20 miles
e• 26 miles

Please tell me exactly how you came up with your answer

Thank you!!
First draw a picture - see attachment.

Then the required distance is twice the hypotenuse of a right triangle
with sides of 6 and 8. You can use Pythagoras's theorem to compute
this. Or you can observe that 6 and 8 are twice the sides of a 3,4,5
triangle so the hypotenuse you seek is 10 mile, and so the total distance
is 20 mile.

Method 2: This is a multiple choice question. Therefore do a scale diagram
and measure the distance of off the diagram.

RonL

Did you make a sketch?

Two cars start off at the same point on a straight road facing opposite directions.
Each car drives for six miles, takes a left turn, and drives for eight miles.
How far apart are the two cars?
(a) 2 miles . (b) 11 miles . (c) 14 miles . (d) 20 miles . (e) 26 miles
Code:
                            *
/ |
/   | 8
6     /     |
* - - - * - - - *
|     /     6
8 |   /
| /
*

Using Pythagorus, each car is $\sqrt{6^2+8^2} = 10$ miles from the starting point.

. . Therefore, they are $20$ miles apart.