# Need Help with this distance problem

• Nov 23rd 2006, 10:48 PM
Need Help with this distance problem
• Two cars start off at the same point on a straight road facing opposite directions. Each car drives for six miles, takes a left turn, and drives for eight miles. How far apart are the two cars?
a• 2 miles
b• 11 miles
c• 14 miles
d• 20 miles
e• 26 miles

Please tell me exactly how you came up with your answer

Thank you!!:confused:
• Nov 23rd 2006, 11:25 PM
CaptainBlack
Quote:

Originally Posted by adamnn2006
• Two cars start off at the same point on a straight road facing opposite directions. Each car drives for six miles, takes a left turn, and drives for eight miles. How far apart are the two cars?
a• 2 miles
b• 11 miles
c• 14 miles
d• 20 miles
e• 26 miles

Please tell me exactly how you came up with your answer

Thank you!!:confused:

First draw a picture - see attachment.

Then the required distance is twice the hypotenuse of a right triangle
with sides of 6 and 8. You can use Pythagoras's theorem to compute
this. Or you can observe that 6 and 8 are twice the sides of a 3,4,5
triangle so the hypotenuse you seek is 10 mile, and so the total distance
is 20 mile.

Method 2: This is a multiple choice question. Therefore do a scale diagram
and measure the distance of off the diagram.

RonL
• Nov 23rd 2006, 11:36 PM
Soroban

Did you make a sketch?

Quote:

Two cars start off at the same point on a straight road facing opposite directions.
Each car drives for six miles, takes a left turn, and drives for eight miles.
How far apart are the two cars?
(a) 2 miles . (b) 11 miles . (c) 14 miles . (d) 20 miles . (e) 26 miles

Code:

                            *                           / |                         /  | 8                 6    /    |             * - - - * - - - *             |    /    6           8 |  /             | /             *

Using Pythagorus, each car is $\displaystyle \sqrt{6^2+8^2} = 10$ miles from the starting point.

. . Therefore, they are $\displaystyle 20$ miles apart.