Prove that the perpendicular bisectors of two nonparallel chords that are not diameters intersect at the center of the circle.
I have some of the problem, but I'm having trouble proving it's the center.
The perpendicular bisector of any chord goes through the center of a circle. This problem is stating that you have 2 non-parallel chords that are not diameters. It is NOT saying that the perpendicular bisectors are not diameters. So, ANY perpendicular bisector of any chord on a circle will intersect at the center of the circle.