Thread: Triangle ABC

The vertices of triangle ABC are A(-2,1), B(4,8)
and C(14,-3). If point M(h,0) lies on line segment AC, find h.

I found the slope of AC to be -1/4.

I then did the following:

-1/4 = (0-1)/(h + 2)

I found h to be 2 but the answer is h = -3.

What did I do wrong?

Originally Posted by magentarita

The vertices of triangle ABC are A(-2,1), B(4,8)
and C(14,-3). If point M(h,0) lies on line segment AC, find h.

I found the slope of AC to be -1/4.

I then did the following:

-1/4 = (0-1)/(h + 2)

I found h to be 2 but the answer is h = -3.

What did I do wrong?

i got h=2

Originally Posted by magentarita

The vertices of triangle ABC are A(-2,1), B(4,8)
and C(14,-3). If point M(h,0) lies on line segment AC, find h.

I found the slope of AC to be -1/4.

I then did the following:

-1/4 = (0-1)/(h + 2)

I found h to be 2 but the answer is h = -3.

What did I do wrong?

Try sketching the triangle on a cartesian plane . h can't be -3 or else it is out of the line AC.

I knew that my answer was correct. Math books tend to have many typos.