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Originally Posted by moose51 solve for x Use the Pythagorean theorem, noting that the hypotenuse has length
could you do x/8 by x+6/20 ?
Originally Posted by moose51 could you do x/8 by x+6/20 ? You will need to form your question more clearly. Could one do what? The Pythagorean theorem will work here. Your hypotenuse has length and the two legs are of length and Set up the equation, expand, and solve for
ok but tell me if im doing this correctly i started with: (x+6)2 + (20)2 = (x+8)2 x2+12x+36+400=x2+16x+64 x2+12x+372=x2+16x x2+372=x2+4x 4x=372 x=93 but i think i did something wrong
Originally Posted by moose51 ok but tell me if im doing this correctly i started with: (x+6)2 + (20)2 = (x+8)2 x2+12x+36+400=x2+16x+64 x2+12x+372=x2+16x x2+372=x2+4x 4x=372 x=93 but i think i did something wrong That is correct.