1. Find x

solve for x

2. Originally Posted by moose51
solve for x
Use the Pythagorean theorem, noting that the hypotenuse has length $x+8.$

3. could you do x/8 by x+6/20 ?

4. Originally Posted by moose51
could you do x/8 by x+6/20 ?
You will need to form your question more clearly. Could one do what?

The Pythagorean theorem will work here. Your hypotenuse has length $x+8,$ and the two legs are of length $x+6$ and $20.$ Set up the equation, expand, and solve for $x.$

5. ok but tell me if im doing this correctly i started with:

(x+6)2 + (20)2 = (x+8)2
x2+12x+36+400=x2+16x+64
x2+12x+372=x2+16x
x2+372=x2+4x
4x=372
x=93

but i think i did something wrong

6. Originally Posted by moose51
ok but tell me if im doing this correctly i started with:

(x+6)2 + (20)2 = (x+8)2
x2+12x+36+400=x2+16x+64
x2+12x+372=x2+16x
x2+372=x2+4x
4x=372
x=93

but i think i did something wrong
That is correct.