Q=(x,y,2)
& P=(0,0,h)
THEREFORE,QP=-x i -y j +(h-2) k.
unit vector of QP=[-x i -y j+(h-2)k]/sqrt.(x^2+y^2+(h-2)^2)
Find an expression for the unit vector directed from point Q(x, y, 2) to point P located on the z-axis at a height h above the x-y plane.
Answer: (-x, -y, h-2)/√(x2+y2+(h-2)^2
can somebody help me how to get that answers given?
can help me step by step?
thank you...