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Math Help - [SOLVED] expression for unit vector

  1. #1
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    Exclamation [SOLVED] expression for unit vector

    Find an expression for the unit vector directed from point Q(x, y, 2) to point P located on the z-axis at a height h above the x-y plane.


    Answer: (-x, -y, h-2)/√(x2+y2+(h-2)^2


    can somebody help me how to get that answers given?
    can help me step by step?
    thank you...


    Last edited by ab.empire; March 1st 2009 at 03:32 AM. Reason: forgot to include right question
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  2. #2
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    Q=(x,y,2)

    & P=(0,0,h)

    THEREFORE,QP=-x i -y j +(h-2) k.

    unit vector of QP=[-x i -y j+(h-2)k]/sqrt.(x^2+y^2+(h-2)^2)
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  3. #3
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    Quote Originally Posted by sbcd90 View Post
    Q=(x,y,2)

    & P=(0,0,h)

    THEREFORE,QP=-x i -y j +(h-2) k.

    unit vector of QP=[-x i -y j+(h-2)k]/sqrt.(x^2+y^2+(h-2)^2)

    thx sbcd90. Appreciate ur help.
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