In the accompanying figure, ΔABC is given with . Can you construct a proof based on the diagram shown, that ∠ABC ∠ACB? (This was Euclid's pons asinorum).
Now I tried looking up pons asinorum proofs online but couldn't quite find one that made sense to me.
Here is my work so far:
Know: m∠BDE = m∠CDF (By the vertical pair theorem that vertical angles have equal measures)
ΔABC is isosceles, so isn't m∠ABC = m∠ACB by the Isosceles Triangle Theorem? And thus ∠ABC ∠ACB? Or is that what I was supposed to prove in the first place?
I am quite confused here
Any help is greatly appreciated.
Thank you very much for your time.