See attachment before reading.

PART 1: angles around D

PART 2: angles in triangle DCE

PART 3: x = x

PART 4: Returning to angles around D

Feel free to ask any question if something is unclear

Results 1 to 4 of 4

- February 23rd 2009, 05:14 AM #1

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- February 23rd 2009, 06:50 AM #2

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- February 23rd 2009, 07:57 AM #3

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Hello, J0naz!

I have a solution, but I'm sure someone will find a shorter one.

Given: .

Find: .Code:A o * * * * 30° * * * * * * * * E * * α o * * * * * θ *α * x * B o * * * * * * * o * * * o C D

Since is isosceles,

In

. . Hence: . .[1]

In

. . Hence: .

In isosceles triangle

Then: . .[2]

At vertex , we have: .

Substitute [1] and [2]: .

. . Therefore: .

- February 23rd 2009, 10:45 AM #4

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## ok,

thank you guys for the help.

But i think unforturnally this one was a little bit over my skill.

I understand your explanation in the beginning, but then its to mutch for me. I have just started the math course so hopfully i will understand it later on.

But thank you for your time anyway, maybe I come back another day with new questions.

Have a nice day

/Jonas