Results 1 to 4 of 4

Math Help - Argh. lost ! Volume

  1. #1
    Newbie
    Joined
    Nov 2006
    Posts
    2

    Exclamation Argh. lost ! Volume

    h=1.35

    r = 12.5

    V = x3.14xr2xh - 2/3xr2xh

    Can someone figure out doing that one ?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,914
    Thanks
    779
    Hello, Gundel!

    h = 1.35, r = 12.5

    V \:= \:\frac{1}{2}\pi r^2h - \frac{2}{3}r^2h

    Can someone figure out doing that one ? . . . figure out what ?

    Are you asking us to do your arithmetic for you?
    Don't you have a calculator?

    V \;= \;\left(\frac{1}{2} \times \pi \times 12.5^2 \times 1.35\right) - \left(\frac{2}{3} \times 12.5^2 \times 1.35\right)

    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Nov 2006
    Posts
    2

    Arrow wop

    the thing is that i'm a **** to math. so need someone to tell me how to do it
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor Quick's Avatar
    Joined
    May 2006
    From
    New England
    Posts
    1,024
    Quote Originally Posted by Gundel View Post
    the thing is that i'm a **** to math. so need someone to tell me how to do it
    What is the value of x\times y when x=2 and y=3?

    So what is the value of \frac{1}{2}\pi r^2h-\frac{2}{3}r^2h when r=12.5 and h=1.35?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Argh! Not story problems!!!
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: March 7th 2010, 12:20 PM
  2. Lagrange Argh...
    Posted in the Calculus Forum
    Replies: 5
    Last Post: October 17th 2009, 08:28 PM
  3. Argh!! Really stuck!! Please help
    Posted in the Differential Equations Forum
    Replies: 5
    Last Post: April 10th 2009, 05:27 AM
  4. Old math tests... Argh!
    Posted in the Statistics Forum
    Replies: 2
    Last Post: May 28th 2007, 10:25 AM
  5. Argh
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: October 6th 2005, 09:18 AM

Search Tags


/mathhelpforum @mathhelpforum