Finding the area of irregular figures

• February 5th 2009, 06:50 PM
Erynn S
Finding the area of irregular figures
How do I find the area of a figure with different measurments?(Wink)
• February 5th 2009, 06:53 PM
topher0805
Squares and Rectangles: Area is equal to length multiplied by width.

$A = lw$

Circles: Area is equal to pi multiplied by the square of the radius.

$A = \pi r^2$

Triangles: Area is equal to one half of the base multiplied by the height.

$A = \frac{1}{2}bh$

I'm not exactly sure what you are asking, so if that doesn't answer your question then be more specific.
• February 5th 2009, 08:07 PM
Erynn S
the shapes are nnot perfect squares and I can't figure out how to draw the figure to shoew you but the highths are 4m and 2m, the width is 3m and 6m they are shaped like rooms with different size walls
Does that make any scence?
• February 5th 2009, 09:31 PM
Slugzzz
RE:
Break the figure up into different shapes. For example... a triangle and a rectangle... and you know how to find the areas of those ;-)
• February 5th 2009, 09:51 PM
mr fantastic
Quote:

Originally Posted by Erynn S
the shapes are nnot perfect squares and I can't figure out how to draw the figure to shoew you but the highths are 4m and 2m, the width is 3m and 6m they are shaped like rooms with different size walls
Does that make any scence?

If you can't be specific about the shape then I'm afraid that only general advice (like what's been given) can be given.
• February 6th 2009, 06:06 AM
HallsofIvy
You should be aware that just knowing the lengths of the sides is NOT generally sufficient to tell you the area of a figure. You also need to know at least some of the angles. For example, there exist an infinite number of parallelograms with sides of length "3" and "4" but with different angles and different areas.