could someone help explain how to solve this?
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Lable G so that GCE is a diameter. The arc(DE)=124 so that arc(DG)=56. Therefore angle(DEC)=28.
Originally Posted by Haris could someone help explain how to solve this? angle BDC=90 .......... radius is perpendicular to tangent at point of contact angle EDC= 90-62=28 angle DEC=angleEDC=28 ............................. since DC=CE angle CEF= angleDEF-angleDEC=62-28=34
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