Hello, mathhomework!
From a point A, the bearing of a radar mast, M, is 048 degrees.
From a second point B, which is 40 m due east of A,
the bearing of the radar mast is 015 degree.
Find angle AMB.
My answer is angle AMB = 33. .Am I right? . . . . Yes! Code:
P Q M
: : *
: : * *
: : * *
: *: *
: * :15°*
: * : *
:48° * : *
: * 42° 90° :*
- * - - - - - - - * - - - - - - -
A 40 B
$\displaystyle \angle PAM = 48^o \quad\Rightarrow\quad \angle MAB = 42^o$
$\displaystyle \angle QBN = 15^o,\:\angle QBA = 90^o \quad\Rightarrow\quad \angle MBA = 105^o$
$\displaystyle \text{In }\Delta AMB\!:\;\angle ANB \:=\:180^o - 42^o - 105^o \;=\;\boxed{33^o} $