# Could Really use Help in Geometery HW Please!

• Nov 1st 2006, 06:26 PM
OnMyWayToBeAMathProffesor
Could Really use Help in Geometery HW Please!

Attachment 1169
• Nov 1st 2006, 06:40 PM
Quick
move the red points to fill in the answers to 12-16 (the diagram might take a while to load at first)

For the other problems, it looks like you don't know what a linear pair is.

A linear pair is two angles sharing a side and a line (such as angles 3 and 4 in the diagram), they equal 180. Can you finish the rest of the problems?
• Nov 1st 2006, 06:48 PM
OnMyWayToBeAMathProffesor
Quote:

Originally Posted by Quick
move the red points to fill in the answers to 12-16 (the diagram might take a while to load at first)

For the other problems, it looks like you don't know what a linear pair is.

A linear pair is two angles sharing a side and a line (such as angles 3 and 4 in the diagram), they equal 180. Can you finish the rest of the problems?

i still dont get it, how can i find the answer wen i know nothing, i would have to find it in terms of a varible, i dont understand and the triangle was really cool.:)
• Nov 1st 2006, 07:01 PM
Quick
Quote:

Originally Posted by OnMyWayToBeAMathProffesor
i still dont get it, how can i find the answer wen i know nothing, i would have to find it in terms of a varible, i dont understand and the triangle was really cool.:)

I think your main problem is linear pairs. Angles AXB and BXC are a linear pair, after moving the points around, what can you find out about linear pairs?

Tell me if you figure it out :)
and please, if you quote this, remove the [draw]Point (40,100) [label ('A')]; Point (140,100) [label ('C')]; Point (90,30) [label ('B')]; Line (1,2); Point on object (4,.5) [label ('X')]; Ray (3,5); Angle (1,5,3,30,120,'Angle AXB = '); Angle (2,5,3,30,135,'Angle BXC = '); Calculate (30,150,'AXB + BXC = ','A B +') (8,7);[/draw] from the quote
• Nov 1st 2006, 07:08 PM
OnMyWayToBeAMathProffesor
thanxs for the help, this is wat i got, are these right because we mite have a pop quiz on this, Attachment 1172
• Nov 1st 2006, 07:12 PM
Quick
I see some errors in your table for the parallel lines diagram, such as KON equals 35 degrees. Do you know the parallal postulates?
• Nov 1st 2006, 07:14 PM
OnMyWayToBeAMathProffesor
Replay To Quick
I am somewhat familar with them. Except for that, is everything rite? thanxs
• Nov 1st 2006, 07:22 PM
Quick
Quote:

Originally Posted by OnMyWayToBeAMathProffesor
I am somewhat familar with them. Except for that, is everything rite? thanxs

I see a few errors in 12-16

Notice that (m means "measure of angle"): $m1+m2+m3=180$

Thus: $m1+m2=180-m3$

And that: $m3+m4=180$

Therefore: $m4=180-m3$

Therefore: $m1+m2=m4$

I would use that info to check your answers, I DON'T RECOMMEND USING IT TO FIND THE ANSWER!

Anyway, I'm done for the night so you'll have to check over yourself... Ciao
• Nov 1st 2006, 07:32 PM
OnMyWayToBeAMathProffesor
Tahnxs A Lot
Thanxs A Lot I Really Appricated Ur Help. Ur Very Smart For A 15 Year Old. Goodnight:) :) :) :) :d :d