# Could Really use Help in Geometery HW Please!

• November 1st 2006, 05:26 PM
OnMyWayToBeAMathProffesor
Could Really use Help in Geometery HW Please!
This is my geometery page below. Im not sure about this page. The answers i didnt get are the one that are balnk and sometimes i think that the answer i put in are wrong, please help!!! really need it, on "The Traingle Sum Theory"

Attachment 1169
• November 1st 2006, 05:40 PM
Quick
Sorry, your Web browser is not Java compatible. This prototype will not be of much interest to you.
move the red points to fill in the answers to 12-16 (the diagram might take a while to load at first)

For the other problems, it looks like you don't know what a linear pair is.

A linear pair is two angles sharing a side and a line (such as angles 3 and 4 in the diagram), they equal 180. Can you finish the rest of the problems?
• November 1st 2006, 05:48 PM
OnMyWayToBeAMathProffesor
Reply To First Post
Quote:

Originally Posted by Quick
Sorry, your Web browser is not Java compatible. This prototype will not be of much interest to you.
move the red points to fill in the answers to 12-16 (the diagram might take a while to load at first)

For the other problems, it looks like you don't know what a linear pair is.

A linear pair is two angles sharing a side and a line (such as angles 3 and 4 in the diagram), they equal 180. Can you finish the rest of the problems?

i still dont get it, how can i find the answer wen i know nothing, i would have to find it in terms of a varible, i dont understand and the triangle was really cool.:)
• November 1st 2006, 06:01 PM
Quick
Quote:

Originally Posted by OnMyWayToBeAMathProffesor
i still dont get it, how can i find the answer wen i know nothing, i would have to find it in terms of a varible, i dont understand and the triangle was really cool.:)

Sorry, your Web browser is not Java compatible. This prototype will not be of much interest to you.
I think your main problem is linear pairs. Angles AXB and BXC are a linear pair, after moving the points around, what can you find out about linear pairs?

Tell me if you figure it out :)
and please, if you quote this, remove the [draw]Point (40,100) [label ('A')]; Point (140,100) [label ('C')]; Point (90,30) [label ('B')]; Line (1,2); Point on object (4,.5) [label ('X')]; Ray (3,5); Angle (1,5,3,30,120,'Angle AXB = '); Angle (2,5,3,30,135,'Angle BXC = '); Calculate (30,150,'AXB + BXC = ','A B +') (8,7);[/draw] from the quote
• November 1st 2006, 06:08 PM
OnMyWayToBeAMathProffesor
thanxs for the help, this is wat i got, are these right because we mite have a pop quiz on this, Attachment 1172
• November 1st 2006, 06:12 PM
Quick
I see some errors in your table for the parallel lines diagram, such as KON equals 35 degrees. Do you know the parallal postulates?
• November 1st 2006, 06:14 PM
OnMyWayToBeAMathProffesor
Replay To Quick
I am somewhat familar with them. Except for that, is everything rite? thanxs
• November 1st 2006, 06:22 PM
Quick
Quote:

Originally Posted by OnMyWayToBeAMathProffesor
I am somewhat familar with them. Except for that, is everything rite? thanxs

I see a few errors in 12-16

Notice that (m means "measure of angle"): $m1+m2+m3=180$

Thus: $m1+m2=180-m3$

And that: $m3+m4=180$

Therefore: $m4=180-m3$

Therefore: $m1+m2=m4$

I would use that info to check your answers, I DON'T RECOMMEND USING IT TO FIND THE ANSWER!

Anyway, I'm done for the night so you'll have to check over yourself... Ciao
• November 1st 2006, 06:32 PM
OnMyWayToBeAMathProffesor
Tahnxs A Lot
Thanxs A Lot I Really Appricated Ur Help. Ur Very Smart For A 15 Year Old. Goodnight:) :) :) :) :d :d