I have no idea on Geometry and I have a question:

The sides BC and AD of a quadrilateral ABCD are parallel. X is the midpoint of AB and Y is a point on the side CD such that CY = 3DY. Find the area of the triangle XYA if the area of the triangle ABC is 120cm squared and the area of the triangle ABD is 160cm squared.

I worked out that:

angle ABD = angle CBD

angle DAC = angle ACB

That's all I could come up with.

Thanks a lot!