I have no idea on Geometry and I have a question:
The sides BC and AD of a quadrilateral ABCD are parallel. X is the midpoint of AB and Y is a point on the side CD such that CY = 3DY. Find the area of the triangle XYA if the area of the triangle ABC is 120cm squared and the area of the triangle ABD is 160cm squared.
I worked out that:
angle ABD = angle CBD
angle DAC = angle ACB
That's all I could come up with.
Thanks a lot!