I think you can use the cos rule then sin rule for area of triangle.

cosA = (330^2 + 270^2 - 240^2 )/ (2 * 330 * 270)

Then use the angle value in this.

0.5 * 330 * 270sin(A) = Area of triangle.

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- Oct 30th 2006, 09:35 PM #1robmasterGuest

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