PAQ is a double chord and BHK is a chord of the larger circle. Prove that PH is parallel to KQ.
I seriously don't know how to start this problem. Can anyone please help me?
The other two facts you need concern supplementary angles. These are angles that add up to 180 degrees. So, for instance, angles PAB and BAQ are supplementary because they are 'Angles on a straight line'. And if you could prove that angles PHK and HKQ were supplementary, that would prove that the lines PH and KQ were parallel, because these angles are called 'Interior angles' and interior angles between parallel lines also supplementary.
So this is what you need to show:
- Angle PHB = angle PAB (as explained above)
- Angle PAQ = angle PKQ (can you explain why?)
- Angle PHK + angle HKQ = 180 degrees.
Can you fill in the gaps now?