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Math Help - Simple geometry

  1. #1
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    Simple geometry

    Given that triangle A has its legs with lengths 4 and 7, you want to create another triangle B that's similar where the smaller leg has a length of 5. Determine the length of the other leg. Then determine its hypotenuse.

    My solution:

    4/7 = 5/x means that x = 35/4 so that's the length of the 2nd leg

    Then, I am assuming the hypotenuse will be proportional if the sides are (by default), so it is then:

    (35/4)^2 + 5^2 = x^2 means that x = 5*sqrt(65)/4

    Is this right?
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  2. #2
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     <br /> <br />
x= \sqrt{(\frac{35}{4})^2 + 5^2}<br /> <br />

    I don't know what you did there but if you calculate your x you get twice as much than it really is.
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  3. #3
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    Quote Originally Posted by metlx View Post
     <br /> <br />
x= \sqrt{(\frac{35}{4})^2 + 5^2}<br /> <br />

    I don't know what you did there but if you calculate your x you get twice as much than it really is.
    Um, that equals 5*sqrt(65)/4 so I guess I was right.
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  4. #4
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    ah yea. sorry about that.
    i thought it was the square root of (65/4). not square root of 65 which is then divided by 4. hence why I got twice as much using your method.
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