Given AE congruent BE congruent CE congruent DE Prove Triangle ABC congruent triangle DCB Am I able to say that angle a is congruent to angle due the sides that they are across from all being congruent
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Here is a simple solution: Diagnals of quadrilateral bisect each other. Diagnals of a parallelogram bisect each other. So is a parallelogram. So AB=CD. In and , BC is common side; AC=BD and AB=CD. SO
I cant say anything aboiut a pallogram because we are missing a whole side of the parallelogram, ok I see I didnt see you say join AD
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