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Math Help - Proof

  1. #1
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    Proof

    Given AE congruent BE congruent CE congruent DE

    Prove Triangle ABC congruent triangle DCB

    Am I able to say that angle a is congruent to angle due the sides that they are across from all being congruent
    Attached Thumbnails Attached Thumbnails Proof-paint.bmp  
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  2. #2
    Junior Member
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    Here is a simple solution:

     Join A  and   D.

    AE=BE=CE=DE

    Diagnals of quadrilateral ABCD bisect each other.
    Diagnals of a parallelogram bisect each other.
    So  ABCD is a parallelogram.
    So AB=CD.
    In \triangle{ABC} and \triangle{BCD},
    BC is common side;
    AC=BD
    and AB=CD.
    SO  \triangle{ABC} \cong{DCB}
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  3. #3
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    Its not a parallelogram

    I cant say anything aboiut a pallogram because we are missing a whole side of the parallelogram, ok I see I didnt see you say join AD
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