Given AE congruent BE congruent CE congruent DE
Prove Triangle ABC congruent triangle DCB
Am I able to say that angle a is congruent to angle due the sides that they are across from all being congruent
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Here is a simple solution:
Diagnals of quadrilateral bisect each other.
Diagnals of a parallelogram bisect each other.
So is a parallelogram.
In and ,
BC is common side;
I cant say anything aboiut a pallogram because we are missing a whole side of the parallelogram, ok I see I didnt see you say join AD
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