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Math Help - Geometry Applications

  1. #1
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    Geometry Applications

    Hi

    In a parallelogram ABCD, the diagonal BD is perpendicular to AB. If the diagonals intersect at T, prove that AD^2 = AT^2 + 3TD^2.

    Ummm I don't seem to get this problem (e.g. how the diagram's supposed to look - diagonal BD is perpendicular to AB?). Could someone please give me a few hints?

    Thanxx
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  2. #2
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    never mind
    Last edited by skeeter; January 21st 2009 at 02:58 PM. Reason: ... interpreted the problem incorrectly.
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  3. #3
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    Hello, xwrathbringerx!

    I'm still working on a proof, but I'll give you a sketch . . .


    In parallelogram ABCD, the diagonal BD is perpendicular to AB.
    If the diagonals intersect at T, prove that: . AD^2 \:=\:AT^2 + 3TD^2
    Code:
         A                 B
          o - - - - - - - o
            \ *           * \
              \   *       *   \
                \     *   *     \
                  \       o T     \
                    \     *   *     \
                      \   *       *   \
                        \ *           * \
                          o - - - - - - - o
                         D                 C
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