If the area of a disc...

**ceasar_19134** · October 24th 2006, 12:16 PM

If the area of a disc inscribed in a square is 36pi^2, what is the area of the square?

**topsquark** · October 24th 2006, 12:22 PM

Originally Posted by ceasar_19134

If the area of a disc inscribed in a square is 36pi^2, what is the area of the square?

If the disc is inscribed in the square, then we know that one side of the square is twice the radius of the circle. The area of the square is $36 \pi ^2$ (typo?) so the radius must be $6 \sqrt{ \pi }$ , thus the side of the square is $12 \sqrt{ \pi }$ and thus the area of the square is $\left ( 12 \sqrt{ \pi } \right ) ^2 = 144 \pi$ .

-Dan

**ceasar_19134** · October 27th 2006, 07:24 AM

The area of the disc is 36pi^2, not the square.

**CaptainBlack** · October 27th 2006, 07:52 AM

Originally Posted by ceasar_19134

If the area of a disc inscribed in a square is 36pi^2, what is the area of the square?

If the pi^2 is a typo it is already answered here

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