If the area of a disc inscribed in a square is 36pi^2, what is the area of the square?

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- Oct 24th 2006, 12:16 PMceasar_19134If the area of a disc...
If the area of a disc inscribed in a square is 36pi^2, what is the area of the square?

- Oct 24th 2006, 12:22 PMtopsquark
If the disc is inscribed in the square, then we know that one side of the square is twice the radius of the circle. The area of the square is $\displaystyle 36 \pi ^2$ (typo?) so the radius must be $\displaystyle 6 \sqrt{ \pi }$, thus the side of the square is $\displaystyle 12 \sqrt{ \pi }$ and thus the area of the square is $\displaystyle \left ( 12 \sqrt{ \pi } \right ) ^2 = 144 \pi$.

-Dan - Oct 27th 2006, 07:24 AMceasar_19134
The area of the disc is 36pi^2, not the square.

- Oct 27th 2006, 07:52 AMCaptainBlack
If the pi^2 is a typo it is already answered here