hmmm i really dont know how angle v is 180... you wrote any three sides of an angle = 180 so i just subsituded angle v for 180

guess that was wrong huh? i dont know... i feel stupid

V = the vertex angle

B = one base angle

V + 2B = 180

V = 2B - 40

the bottom side is shortest

**i think**.

correct ... it's opposite angle x, the smallest angle. your given picture is not drawn to scale.
and i got x2 - 2x - 80=0

(x+10)(x-8)=0

x+10=0 i subbtracted 10 from zero and got x-10

and then i got x=+8 but

**when i check +8 it didnt add up** so used -10

my mistake ... original equation should be
and hmmmmm so far i wrote

AD=BC is given and then AD is parral to ab and BC is parral to ab is given and then i wrote what DAB and CBA = right triangles, ad and bc congruent to itsself therefore DAB and CBA = a.s.a

there you go ... clean it up like your teacher wants.