i have the slightest idea on what to do can someone please explain? step by step and conclude on how the answer was determined?
all help is highly appreciated
for the first one i know AB is parrallel to CD right?
and if agh makes an angle that equals to 2x and ghc = x-30
does that mean i have to 2x + x-30 = 180?
this is confusing... some basic rules i guess if any one can give out im really lost guys i feel llike i cant get the right anwers
#1 hint ...
same side interior angles are supplementary.
#2 hints ...
alternate interior angles are equal
$\displaystyle \angle LQP$ and $\displaystyle \angle PQV$ are supplementary
#3 hints ...
$\displaystyle \angle V = 2\angle B - 40$
three angles of any triangle sum to 180.
#4 hint ...
alternate interior angles are equal
#5 hints ...
three angles of any triangle sum to 180.
$\displaystyle \angle ACB$ and $\displaystyle \angle BCD$ are supplementary
#6 hints ...
exterior angle of a triangle = sum of the two remote interior angles
shortest side of a triangle is opposite the smallest angle
#7 hints ...
angle-side-angle
CPCTC
last one ...
$\displaystyle x^2 - 2x - 80 = 0$
left side will factor.
Excellent... mind checkin over my answers??? im stuck on like two problems though...
for #1 i have x = 70 , agh = 140, and ghc = 40
#2 i have... M<2 = 62 degrees and m<3 = 118
#3 ... 2(110)-40=180 and x = 110
#4 i have m<x = 50
#5 m<d = 80
m<cbd = 30
m<bcd = 70
m<abc=30
#6 i am stuck in..... but i have x = 35 , R=80 and angle 1 = 65 but i dont know which side is the shortest? how can i determine?
#7 im working on...
and #8 how do i begin factoring? do i do (x+1)(x=1) + 2x=80??
hmmm i really dont know how angle v is 180... you wrote any three sides of an angle = 180 so i just subsituded angle v for 180
guess that was wrong huh? i dont know... i feel stupid
the bottom side is shortest i think.
and i got x2 - 2x - 80=0
(x+10)(x-8)=0
x+10=0 i subbtracted 10 from zero and got x-10
and then i got x=+8 but when i check +8 it didnt add up so used -10
and hmmmmm so far i wrote
AD=BC is given and then AD is parral to ab and BC is parral to ab is given and then i wrote what DAB and CBA = right triangles, ad and bc congruent to itsself therefore DAB and CBA = a.s.a