• January 9th 2009, 01:48 PM
dgenerationx2
in attachments
• January 9th 2009, 02:55 PM
joeyundis
As far as I can see, the only way to get something like a square would be to plot a point at (5,0)
• January 9th 2009, 06:54 PM
Soroban
Hello, dgenerationx2!

You couldn't type the question for us?

Quote:

Quadrilateral $ABCD$ has vertices with coordinates:
. . $A(1,-4),\;\;B(-3,0),\;\;C(1,4)$

Determine the coordinates of $D$ for which $ABCD$ is a square.

Did you make a sketch?
Code:

```              | (1,4)               |  o C               | *  *               *      *             * |        *         B *  |          *  D     - - o - - | - - - - - - o - -     (-3,0)*  |          *             * |        *               *      *               | *  *               |  o A               | (1,-4)```

You can "eyeball" where $D$ is . . . can't you?