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Math Help - 4 more math questions

  1. #1
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    4 more math questions

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    think 17 is A. 25.6 not sure
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by dgenerationx2 View Post
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    think 17 is A. 25.6 not sure
    you are correct (you used Pythagoras' Theorem, i suppose)

    what about the others?

    for 23 and 27 recall that the diagonals of a rectangle bisect each other (cut each other at their midpoints)

    hint for 29, note that the diagonals are the same length, so AC = BD
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  3. #3
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    Quote Originally Posted by dgenerationx2 View Post
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    think 17 is A. 25.6 not sure
    17)
    <br /> <br />
\overline{NL} = 2\times\overline{JL} = 2\times 12.8 = 25.6<br />

    OR

    <br />
\overline{NL} = \overline{MK}<br />

    <br />
\overline{MK} = \sqrt{\overline{NM}^2 + \overline{NK}^2} = \sqrt{16^2 +20^2} = \sqrt 656 \doteq 25.6<br />

    23) and 27)
    <br />
\overline {RT} = \overline {TP} = \overline {PS}<br />

    <br />
\sqrt{(\overline {RT}+ \overline {TP})^2 - \overline {PS}^2} = \overline {SR}<br />

    <br />
\sqrt{(2\times\overline{RT})^2 - \overline{PS}^2} = \overline{SR}<br />

    <br />
\sqrt{(2\times5)^2 - 5^2} = \overline {SR}<br />

    <br />
\overline {SR} = \sqrt {75} = 5\sqrt{3} \doteq 8.7<br />

    29)
    <br />
\overline{AC} = 3x<br />

    <br />
\overline{BD} = 7x - 8<br />

    <br />
\overline{AC} = \overline {BD}<br />

    <br />
3x = 7x - 8 <br />

    <br />
4x = 8 <br />

    <br />
x = 2<br />

    <br />
\overline{AC} = \overline {BD} = 3x = 3\times2 = 6<br />
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