Originally Posted by

**AfterShock** I don't see how that has anything to do with Calculus. Therefore, the fact that you haven't had Calculus in a while should not make a difference for this problem. Unless, that is, you're talking about the arc length of a function, which is obtained given,

an x = f(y), where f(y) is a function such that its derivative f'(x) is continuous on the closed interval [a, b]. The arc length, then, of f from y = a to y = b is the integral:

integral(sqrt(1 + [f'(x)]^2))dy, from a to b).