Prove that: 1)AE=BF 2)EF>BF I have done 1 but i just don't know how to do 2.
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Originally Posted by Tom1234 Prove that: 1)AE=BF 2)EF>BF I have done 1 but i just don't know how to do 2. Easy to prove that $\displaystyle OK=OL;\angle AKO=\angle BLO $ then triangle $\displaystyle AKO$=triangle $\displaystyle BLO$ So $\displaystyle \angle AOE=\angle BOF $=>$\displaystyle AE=BF$
thank you but what about the other question?
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