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Thread: Rectangle

  1. #1
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    Rectangle

    A rectangle is three times as long as it is wide. If its length and width are both decreased by 2cm, its area is decreased by 36cm^2. Find its original dimensions.
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    Member Last_Singularity's Avatar
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    Quote Originally Posted by magentarita View Post
    A rectangle is three times as long as it is wide. If its length and width are both decreased by 2cm, its area is decreased by 36cm^2. Find its original dimensions.
    Denote the original length to be $\displaystyle L$ and its original width to be $\displaystyle W$.

    From the first sentence, you know $\displaystyle 3W=L$

    The second one tells you that $\displaystyle (L-2)(W-2)=LW-36$

    Solve the resulting two equations.
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  3. #3
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    ok...

    Quote Originally Posted by Last_Singularity View Post
    Denote the original length to be $\displaystyle L$ and its original width to be $\displaystyle W$.

    From the first sentence, you know $\displaystyle 3W=L$

    The second one tells you that $\displaystyle (L-2)(W-2)=LW-36$

    Solve the resulting two equations.
    Thanks. I can take it from here.
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