The vertices of Triangle PQR are P(1, 2), Q(-3, 6) and
R(4, 8). A line through Q is parallel to line segment PR and passes through point (k, 14). Find k.
I know that parallel lines have equal slopes. I first found the slope of line segment PR to be 2/1.
I then equated the slope this way:
2/1 = (14 - 2)/(k - 1)
Solving for k, I got k = 7 but the answer is k = 1.
What did I do wrong and why is the answer 1 not 7?