Solve for x.
Given BD = 7/(2x+4) and AE = 9x - 4. Assume B is the midpoint of AC and D is the midpoint of CE.
Do I equate 7/(2x + 4) to 9x - 4 and solve for x?
Draw a rough sketch of the triangle (see attachment)
Because $\displaystyle \overline{BD} \parallel \overline{AE}$ you know that $\displaystyle 2\cdot |\overline{BD}| = | \overline{AE} |$
Therefore solve for x:
$\displaystyle 2\cdot \left(\dfrac7{2x+4} \right) = 9x-4$