1. ## Line Segment

Solve for x.

Given BD = 7/(2x+4) and AE = 9x - 4. Assume B is the midpoint of AC and D is the midpoint of CE.

Do I equate 7/(2x + 4) to 9x - 4 and solve for x?

2. Originally Posted by magentarita
Solve for x.

Given BD = 7/(2x+4) and AE = 9x - 4. Assume B is the midpoint of AC and D is the midpoint of CE.

Do I equate 7/(2x + 4) to 9x - 4 and solve for x? No

Draw a rough sketch of the triangle (see attachment)

Because $\displaystyle \overline{BD} \parallel \overline{AE}$ you know that $\displaystyle 2\cdot |\overline{BD}| = | \overline{AE} |$

Therefore solve for x:

$\displaystyle 2\cdot \left(\dfrac7{2x+4} \right) = 9x-4$

3. ## yes...

Originally Posted by earboth
Draw a rough sketch of the triangle (see attachment)

Because $\displaystyle \overline{BD} \parallel \overline{AE}$ you know that $\displaystyle 2\cdot |\overline{BD}| = | \overline{AE} |$

Therefore solve for x:

$\displaystyle 2\cdot \left(\dfrac7{2x+4} \right) = 9x-4$
That's exactly what I did.

Thanks