help me solve part (b)
Area of APBC = 2 x Area of triangle OBC + area of sector OAPB, found in part (a)
Area of triangle OBC = 0.5 x base x height, where base = OC and height = perpendicular distance from B to OP.
Height = OB x sin (angle BOP), and angle BOP = 2 x angle BCP (angle at centre = twice angle at circumference.
I hope you can do it now.