Hello, fayeorwhatsoever!
1.) From a point 55 m up the ground on a vertical antenna pole, three cables are stretched
into anchors which are located at the vertices of an equilateral triangle 20 m on a side.
Find the length of each cable if the foot of the pole is equidistant from the anchors.
Looking down at the ground, the anchors are situated like this: Code:
A
*
/|\
/ | \
/ | \
20 / | \ 20
/ | \
/ | \
/ *G \
/ | \
/ | \
B * - - - - * - - - - * C
10 D 10
The pole is at
, which is equidistant from the vertices.
This point is at the centroid of the triangle,
. . which divides the altitude in the ratio 2:1.
Using Pythagorus, we find that the altitude is: . 
Then G is located so that: .  \:=\:\frac{20\sqrt{3}}{3})
A side view of the pole and cable looks like this: Code:
F *
|\
| \
| \
| \
55 | \
| \
| \
| \
| \
G * - - - - * A
(20√3)/3
The pole is: 
The anchor is at 
The length of the cable is the hypotenuse:
. . ^2 \;=\; 3025 + \frac{400}{3} \;=\;\frac{9475}{3})
Therefore: . 