# Math Help - angles problem

1. ## angles problem

thanks

2. Originally Posted by helloying
thanks
(a)
$\angle{DBC}=28$ from this we know $\angle{BCD}=180-2*28=124$. $X+X+\angle{ACB}=180$ and
$X+\angle{ACB}=124$ solving these equations you get $X=56$ and $\angle{ACB}=180 - 2*56=68$. You also know that $\angle{ABC}=2*28=56$. Now, what is $\angle{BAC}$ ? It is $180 -68-56=56$.

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