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Math Help - angles problem

  1. #1
    Member helloying's Avatar
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    angles problem

    thanks
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  2. #2
    Junior Member
    Joined
    Nov 2008
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    Quote Originally Posted by helloying View Post
    thanks
    (a)
    \angle{DBC}=28 from this we know \angle{BCD}=180-2*28=124. X+X+\angle{ACB}=180 and
    X+\angle{ACB}=124 solving these equations you get X=56 and \angle{ACB}=180 - 2*56=68. You also know that \angle{ABC}=2*28=56. Now, what is \angle{BAC} ? It is 180 -68-56=56.


    (b) and (c) are much more easier questions, try to solve them. If you do not succeed ask here again. Good luck!
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