angles problem

Quote:

Originally Posted by helloying

thanks

(a)
$\angle{DBC}=28$ from this we know $\angle{BCD}=180-2*28=124$ . $X+X+\angle{ACB}=180$ and
$X+\angle{ACB}=124$ solving these equations you get $X=56$ and $\angle{ACB}=180 - 2*56=68$ . You also know that $\angle{ABC}=2*28=56$ . Now, what is $\angle{BAC}$ ? It is $180 -68-56=56$ .

(b) and (c) are much more easier questions, try to solve them. If you do not succeed ask here again. Good luck!