help appreciated
Hi -
Sorry, you do need a bit more than I said before.
Join BD to form a cyclic quadrilateral ABDE. Then (as in an earlier question you asked) the angle BDC is an exterior angle to this quadrilateral, and so equals angle EAB, the interior opposite angle.
So angle BDC = 70 degrees = angle BFC (angles in the same segment).
Now you can use the fact that angle BFC + angle FCG = 180 degrees to find angle FCE.
OK now?
Grandad