I just want to make sure I did this problem right or not. Please correct me if I 'm wrong.

Find the area of a regular hexagon with side 2* sqrt of 3cm and apothem 3cm.

Here's what I got:

The formula is A=1/2ap, p(perimeter)=6s=6*2sqrtof3=12*sqrtof3.

a(apothem)=1/2s*sqrtof3=1/2*2*sqrtof3=sqrtof3.

A=1/2*sqrtof3*12*sqrtof3=6(sqrtof3)^2=6*3=18.

I'm I correct?

thanks for your help.