explain to me how to solve part (c). i dont undertand.
Help appreciated
Hello, helloying!
Code:M | N | | B* θ | * |* | 13 * 60° | * | * | * | 60° * | * | * | * 9.5 A * 44° S * | * * | * * | * * | * * | * C |
You found that $\displaystyle \angle ABC = 64.1^o$
Note that $\displaystyle \angle ABS = 60^o.$
Hence: $\displaystyle \angle SBC = 4.1^o.$
The bearing of $\displaystyle C$ from $\displaystyle B$ is: .$\displaystyle \theta \:=\:\angle MBC \:=\:180^o - 4.1^o \:=\:175.9^o$