# geometry angle problem

• Dec 7th 2008, 07:36 PM
helloying
geometry angle problem
explain to me how to solve part (c). i dont undertand.

Help appreciated
• Dec 7th 2008, 07:40 PM
bherrell2
Quote:

Originally Posted by helloying
explain to me how to solve part (c). i dont undertand.

Help appreciated

• Dec 7th 2008, 07:47 PM
helloying
Bearing is the angle in degree. Something like north, south, east ,west. used for directions
• Dec 7th 2008, 08:16 PM
Soroban
Hello, helloying!

Code:

                        M                         |       N                |       |                B* θ       |              *  |*       |        13 * 60° | *       |        *        |  *       | 60° *          |  *       |  *              |    * 9.5     A *  44°          S    *       |    *                  *       |          *            *       |                *        *       |                      *  *       |                            * C       |

You found that $\angle ABC = 64.1^o$

Note that $\angle ABS = 60^o.$

Hence: $\angle SBC = 4.1^o.$

The bearing of $C$ from $B$ is: . $\theta \:=\:\angle MBC \:=\:180^o - 4.1^o \:=\:175.9^o$