Originally Posted by
janvdl Since the rope is 100 feet long, then the perimeter of this rectangle must be 100 feet long too.
So we can say:
$\displaystyle P = 100 = 2L + 2W$
And simplify that to:
$\displaystyle 50 = L + W$
And let's rearrange that to:
$\displaystyle L = 50 - W$
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Now let's go to the area (This is going to end up as a simul. equation)
$\displaystyle A = 576 = LW$
Now let's substitute that value we have for the length
$\displaystyle 576 = (50 - W)(W)$
$\displaystyle 576 = 50W - W^2$
$\displaystyle W^2 - 50W + 576 = 0$
Solve for W, and subsequently L.