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Math Help - I have more circle questions. 2nd last batch.

  1. #1
    Junior Member
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    I have more circle questions. 2nd last batch.

    use pics for each question. uploaded in order.

    20. Given: BC is tangent to circle A;

    BD = 17, BC = 15

    AC =

    A. 16
    B. 2
    C. 4
    D. 8

    23. Given: circle P is inscribed in triangle ABC;

    AF = 5, CE = 6, BD = 8

    The perimeter of the triangle is =

    A. 76
    B. 4 *15 (15 is squared = *)
    C. 19
    D. 38

    27. Given: AB, AC, and AD are tangent to circle P and circle Q;

    AB = 6

    Find: AC

    A. 6
    B. 10
    C. 13
    D. 80

    2 questions left. next post
    Attached Thumbnails Attached Thumbnails I have more circle questions. 2nd last batch.-pic-13.gif   I have more circle questions. 2nd last batch.-pic-17.gif   I have more circle questions. 2nd last batch.-pic-20.gif   I have more circle questions. 2nd last batch.-pic-23.gif   I have more circle questions. 2nd last batch.-pic-27.jpeg  

    Last edited by mr fantastic; December 6th 2008 at 01:51 PM. Reason: Deleted Questions 13 and 17 (they were re-posted by the OP in a new thread) Less questions makes for a better thread.
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  2. #2
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    earboth's Avatar
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    Quote Originally Posted by dgenerationx2 View Post
    I don't understand this notation of angles.

    20. Given: BC is tangent to circle A;

    BD = 17, BC = 15

    AC =
    C. 4

    23. Given: circle P is inscribed in triangle ABC;

    AF = 5, CE = 6, BD = 8

    The perimeter of the triangle is =

    D. 38

    27. Given: AB, AC, and AD are tangent to circle P and circle Q;

    AB = 6

    Find: AC

    A. 6


    2 questions left. next post No threats, please!
    to 20:

    Use Pythagorean theorem:
    |AC| = \frac12 \cdot |CD| = \frac12 \cdot \sqrt{17^2-15^2}=4

    to 23:

    Since |AF| = |AE|, |CE| = |CD|, |BD| = |BF|

    all given lengths are used twice. Therefore the circumference is 2(5+6+8) = 38

    to 27:

    For symmetry reasons |AB| = |AC| = |AD|

    Therefore |AC| = 6
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  3. #3
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    Oct 2008
    Posts
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    thanks but still need other one answered.
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