Ok I am having difficulties converting cartesian into equations to parametric/vector equations.
By using the example provided could someone show me how it's done?
Let A(1,5) and u(3,2)
M(x,y) is on the line passing through A with direction u means that exists k real such as AM = k u
Coordinates give the system
x - 1 = 3k
y - 5 = 2k
Parametric equation of the line is the system
x = 3k + 1
y = 2k + 5
To get the cartesian equation you have to eliminate k
2x = 6k + 2
3y = 6k + 15
Difference gives 2x - 3y = -13
A cartesian equation is therefore 2x - 3y + 13 = 0