Ok I am having difficulties converting cartesian into equations to parametric/vector equations.

By using the example provided could someone show me how it's done?

http://img34.picoodle.com/img/img34/...em_dedc78f.jpg

- Dec 2nd 2008, 04:57 AMJoeyCCHow to convert cartesian equations into vector or parametric equations?
Ok I am having difficulties converting cartesian into equations to parametric/vector equations.

By using the example provided could someone show me how it's done?

http://img34.picoodle.com/img/img34/...em_dedc78f.jpg - Dec 2nd 2008, 10:20 AMrunning-gag
Let A(1,5) and

**u**(3,2)

M(x,y) is on the line passing through A with direction**u**means that exists k real such as**AM**= k**u**

Coordinates give the system

x - 1 = 3k

y - 5 = 2k

Parametric equation of the line is the system

x = 3k + 1

y = 2k + 5

To get the cartesian equation you have to eliminate k

2x = 6k + 2

3y = 6k + 15

Difference gives 2x - 3y = -13

A cartesian equation is therefore 2x - 3y + 13 = 0 - Dec 2nd 2008, 10:48 AMSoroban
Hello, JoeyCC!

I believe the vector is: .$\displaystyle \vec v \;=\;(1+3t)\vec i + (5 + 2t)]\vec j$

- Dec 2nd 2008, 10:54 AMJoeyCC
Thanks Man!