1. ## Parallelogram Proof...

Given: Parallelogram ABCD
BC > AB; BK = AB
Prove: 1) CK = CD
2) K is the midpt. of line segment of BC.

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I am really sorry for the inconvenience, but I was having problems with the file attachment. But you can fast forward the drawing speed.

2. let angle ADK = CDK = x. Use the fact that co-interior angles in parallel lines add to 180 to get DCK and then the angle sum of a triangle to get DKC and you are done.