How to prove that sum of opposite angles in any cyclic quadrilateral is 180? With logical reasoning.
Hello, u2_wa!
Prove that sum of opposite angles in any cyclic quadrilateral is 180°?An inscribed angle is measured by one-half its intercepted arc.Code:A * o * * o o * * o o * * o o B o o * o o * * o o * * o o * o o D o o * * o o * * o * * o * C
We have inscribed quadrilateral
. .
Add [1] and [2]:
. .
. . . . . . . . .
. . . . . . . . .
. . . . . . . . .
In a similar manner, we can prove that: .