Hello, u2_wa!

Prove that sum of opposite angles in any cyclic quadrilateral is 180°?An inscribed angle is measured by one-half its intercepted arc.Code:A * o * * o o * * o o * * o o B o o * o o * * o o * * o o * o o D o o * * o o * * o * * o * C

We have inscribed quadrilateral

. .

Add [1] and [2]:

. .

. . . . . . . . .

. . . . . . . . .

. . . . . . . . .

In a similar manner, we can prove that: .