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Math Help - Help me with the angle

  1. #1
    Member helloying's Avatar
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    Help me with the angle

    see the attactment

    thank you
    Attached Thumbnails Attached Thumbnails Help me with the angle-math2.jpg  
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  2. #2
    Junior Member
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    Hello helloying:

    Draw a horizontal line through point E.

    This forms some right triangles with leg measures of 10 and 17 because point E is vertically and horizontally centered inside the rectangle.

    Therefore, the measure of half of angle BEC can be found using the inverse tangent function with the ratio 10/17.

    Double the result.

    Actually, you do not need the horizontal line because half of angle BEC is the same as the measure of angle BAE. And the ratio 20/34 simplifies to 10/17, which brings us back to the same input for the inverse tangent function.


    Cheers,

    ~ Mark
    Last edited by mmm4444bot; November 22nd 2008 at 11:48 PM.
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  3. #3
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    Quote Originally Posted by helloying View Post
    see the attactment

    thank you
    Is ABCD a rectangle? If so:

    1. Split \angle(BEC) into 2 equal parts: \frac12 \angle(BEC)=\alpha

    2. \tan(\alpha)=\dfrac{10}{17}~\implies~\alpha\approx 30.466^\circ

    3. Therefore: \angle(BEC)\approx 60.9^\circ
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