If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?
Hi mate
I guess it is just
$\displaystyle V = \frac{1}{3} Bh $ , where B is the area
V = 192 yd^3 $\displaystyle ;V = \frac{1}{3} Bh $ where B is the area
B = 64 yd^2
=> $\displaystyle V = \frac{1}{3} Bh $
=> $\displaystyle 192 \ yd^3 = \frac{1}{3} 64 \ yd^2 *h$
=> $\displaystyle h = 3*192 \ yd^3 / (64 \ yd^2) = 9 \ yd $
Rapha
By defintion, the volume of a square based pyramid is given by
Vol = (1/3) x Perpendicular Height x Area of Base
Subbing in the known parameters yields
192 = (1/3) x Perpendicular Height x 64
Thus,
the Perpendicular Height = (3 x 192) / 64
Hope this helps,
Regards,
David