# Math Help - Height of Pyramid

1. ## Height of Pyramid

If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?

2. Hi mate

Originally Posted by magentarita
If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?
I guess it is just

$V = \frac{1}{3} Bh$ , where B is the area

V = 192 yd^3 $;V = \frac{1}{3} Bh$ where B is the area
B = 64 yd^2

=> $V = \frac{1}{3} Bh$

=> $192 \ yd^3 = \frac{1}{3} 64 \ yd^2 *h$

=> $h = 3*192 \ yd^3 / (64 \ yd^2) = 9 \ yd$

Rapha

3. Originally Posted by magentarita
If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?

By defintion, the volume of a square based pyramid is given by

Vol = (1/3) x Perpendicular Height x Area of Base

Subbing in the known parameters yields

192 = (1/3) x Perpendicular Height x 64

Thus,

the Perpendicular Height = (3 x 192) / 64

Hope this helps,

Regards,

David

4. ## ok............

Originally Posted by Rapha
Hi mate

I guess it is just

$V = \frac{1}{3} Bh$ , where B is the area

V = 192 yd^3 $;V = \frac{1}{3} Bh$ where B is the area
B = 64 yd^2

=> $V = \frac{1}{3} Bh$

=> $192 \ yd^3 = \frac{1}{3} 64 \ yd^2 *h$

=> $h = 3*192 \ yd^3 / (64 \ yd^2) = 9 \ yd$

Rapha
I thank you.

5. ## ok...............

Originally Posted by David24
By defintion, the volume of a square based pyramid is given by

Vol = (1/3) x Perpendicular Height x Area of Base

Subbing in the known parameters yields

192 = (1/3) x Perpendicular Height x 64

Thus,

the Perpendicular Height = (3 x 192) / 64

Hope this helps,

Regards,

David
I thank you.