If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?
By defintion, the volume of a square based pyramid is given by
Vol = (1/3) x Perpendicular Height x Area of Base
Subbing in the known parameters yields
192 = (1/3) x Perpendicular Height x 64
Thus,
the Perpendicular Height = (3 x 192) / 64
Hope this helps,
Regards,
David