If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?

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- Nov 20th 2008, 06:30 PMmagentaritaHeight of Pyramid
If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?

- Nov 21st 2008, 05:27 PMRapha
Hi mate

I guess it is just

$\displaystyle V = \frac{1}{3} Bh $ , where B is the area

V = 192 yd^3 $\displaystyle ;V = \frac{1}{3} Bh $ where B is the area

B = 64 yd^2

=> $\displaystyle V = \frac{1}{3} Bh $

=> $\displaystyle 192 \ yd^3 = \frac{1}{3} 64 \ yd^2 *h$

=> $\displaystyle h = 3*192 \ yd^3 / (64 \ yd^2) = 9 \ yd $

Rapha - Nov 21st 2008, 05:39 PMDavid24

By defintion, the volume of a square based pyramid is given by

Vol = (1/3) x Perpendicular Height x Area of Base

Subbing in the known parameters yields

192 = (1/3) x Perpendicular Height x 64

Thus,

the Perpendicular Height = (3 x 192) / 64

Hope this helps,

Regards,

David - Nov 21st 2008, 06:40 PMmagentaritaok............
- Nov 21st 2008, 06:41 PMmagentaritaok...............