Height of Pyramid

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November 20th 2008, 06:30 PM
magentarita

Height of Pyramid

If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?
November 21st 2008, 05:27 PM
Rapha

Hi mate

Quote:

Originally Posted by magentarita

If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?

I guess it is just

$V = \frac{1}{3} Bh$ , where B is the area

V = 192 yd^3 $;V = \frac{1}{3} Bh$ where B is the area
B = 64 yd^2

=> $V = \frac{1}{3} Bh$

=> $192 \ yd^3 = \frac{1}{3} 64 \ yd^2 *h$

=> $h = 3*192 \ yd^3 / (64 \ yd^2) = 9 \ yd$

Rapha
November 21st 2008, 05:39 PM
David24

Quote:

Originally Posted by magentarita

If the volume of the pyramid is 192 yd^3 and the area of the base is 64 yd^2, what is the height of the pyramid?

By defintion, the volume of a square based pyramid is given by

Vol = (1/3) x Perpendicular Height x Area of Base

Subbing in the known parameters yields

192 = (1/3) x Perpendicular Height x 64

Thus,

the Perpendicular Height = (3 x 192) / 64

Hope this helps,

Regards,

David
November 21st 2008, 06:40 PM
magentarita

ok............

Quote:

Originally Posted by Rapha

Hi mate

I guess it is just

$V = \frac{1}{3} Bh$ , where B is the area

V = 192 yd^3 $;V = \frac{1}{3} Bh$ where B is the area
B = 64 yd^2

=> $V = \frac{1}{3} Bh$

=> $192 \ yd^3 = \frac{1}{3} 64 \ yd^2 *h$

=> $h = 3*192 \ yd^3 / (64 \ yd^2) = 9 \ yd$

Rapha

I thank you.
November 21st 2008, 06:41 PM
magentarita

ok...............

Quote:

Originally Posted by David24

By defintion, the volume of a square based pyramid is given by

Vol = (1/3) x Perpendicular Height x Area of Base

Subbing in the known parameters yields

192 = (1/3) x Perpendicular Height x 64

Thus,

the Perpendicular Height = (3 x 192) / 64

Hope this helps,

Regards,

David

I thank you.

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