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Math Help - Geometry Proofs help. I am having so much trouble with them.

  1. #1
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    Geometry Proofs help. I am having so much trouble with them.

    Here are a few problems. Give me the reasons. This will make the difference to wether I pass the class for the six weeks. I am a few points away from passing.

    1. Given: Q is the midpoint of PR, R is the midpoint of QS
    Prove: PR = QS

    *Statements*
    a. Q is the midpoint of PR
    b. PQ = QR
    c. R is the midpoint of QS
    d. QR = RS
    e. PQ+QR=QR+RS
    f. PQ+QR=PR, QR+RS=QS
    g. PR=QS

    2. Given: line segment AB =~ line segment DE, line segment BS =~ to line segment EF
    Prove: line segment AC =~ line segment DF

    It is 2 parallel lines. Points ABC are on one line and DEF are on the other.

    *Statements*
    a. line segment AB =~ line segment DE
    b. AB = DE
    c. line segment BS =~ line segment EF
    d. BC = EF
    e. AB+BC=DE+EF
    f. AB+BC=AC, DE+EF=DF
    g. AC = DF
    h. line segment AC =~ line segment DF

    3. Given AB perpendicular to BC, andgle 1 and angle 3 are complementary
    Prove angle 2 =~ angle 3

    *Statements*
    a. AB perpendicular to BC
    b. angle ABC = 90
    c. angle 1 + angle 2 = angle ABC
    d. angle 1 and andgle 2 form a right angle
    e. angle 1 and angle 2 are complementary
    f. angle 1 and angle 3 are complementary
    g. angle 2 =~ angle 3
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by BobGnarley View Post
    Here are a few problems. Give me the reasons. This will make the difference to wether I pass the class for the six weeks. I am a few points away from passing.

    1. Given: Q is the midpoint of PR, R is the midpoint of QS
    Prove: PR = QS

    *Statements*
    a. Q is the midpoint of PR GIVEN
    b. PQ = QR DEFINITION OF MIDPOINT
    c. R is the midpoint of QS GIVEN
    d. QR = RS DEFINITION OF MIDPOINT
    e. PQ+QR=QR+RS ADDITION
    f. PQ+QR=PR, QR+RS=QS SEGMENT ADDITION POSTULATE
    g. PR=QS SUBSTITUTION (e) AND (f).

    2. Given: line segment AB =~ line segment DE, line segment BC =~ to line segment EF
    Prove: line segment AC =~ line segment DF

    It is 2 parallel lines. Points ABC are on one line and DEF are on the other.

    I'M PRETTY SURE YOU STATED THIS ONE INCORRECTLY, BUT I THINK I SEE THE PICTURE. YOU HAVE TWO PARALLEL LINES CUT BY TWO TRANSVERSALS, THUS CUTTING OFF CONGRUENT SEGMENTS ON THE PARALLEL LINES.

    *Statements*
    a. line segment AB =~ line segment DE GIVEN
    b. AB = DE DEFINITION OF CONGRUENT SEGMENTS
    c. line segment BC =~ line segment EF GIVEN
    d. BC = EF DEFINITION OF CONGRUENT SEGMENTS
    e. AB+BC=DE+EF ADDITION
    f. AB+BC=AC, DE+EF=DF SEGMENT ADDITION POSTULATE
    g. AC = DF SUBSTITUTION (e), (f)
    h. line segment AC =~ line segment DF DEFINITION OF CONGRUENT SEGMENTS

    3. Given AB perpendicular to BC, andgle 1 and angle 3 are complementary
    Prove angle 2 =~ angle 3

    IN THIS ONE, YOU HAVE TWO ADJACENT ANGLES 1 AND 2 THAT MAKE UP RIGHT ANGLE ABC. YOU HAVE A THIRD INDEPENDENT ANGLE 3 THAT IS COMPLEMENTARY TO ANGLE 2.

    *Statements*
    a. AB perpendicular to BC GIVEN
    b. angle ABC = 90 PERPENDICULAR LINES MEET TO FORM RIGHT ANGLES
    c. angle 1 + angle 2 = angle ABC ANGLE ADDITION POSTULATE
    d. angle 1 and andgle 2 form a right angle SUBSTITUTION (b), (c)
    e. angle 1 and angle 2 are complementary DEFINITION OF COMPLEMENTARY ANGLES
    f. angle 1 and angle 3 are complementary GIVEN
    g. angle 2 =~ angle 3 TWO ANGLES COMPLEMENTARY TO THE SAME ANGLE ARE CONGRUENT
    DIAGRAMS WOULD'VE BEEN NICE. And by the way, I'm not flaming by using all caps. This is just for contrast. So relax.
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